EMF or Energy: Puzzling Out the Difference

AI Thread Summary
Electromotive force (emf) and energy are distinct concepts in electricity, despite both being represented by the letter "E" in equations. The similarity in notation is coincidental, and some texts use a different symbol to differentiate emf. Emf refers to the voltage generated by a source, while energy pertains to the capacity to do work. Understanding this distinction is crucial for clarity in electrical studies. The discussion emphasizes the importance of notation in avoiding confusion between these two terms.
mushroom993
Messages
1
Reaction score
0
Hai - I am revising and now I am confused - equations for both electromotive force (emf) and energy begin E=... (in different sections of my electricity notes)

Does that mean EMF is a type of energy or am I missing something?

Thanks :)
 
Physics news on Phys.org
Welcome to PF!

Hi mushroom993! Welcome to PF! :smile:

It's just a coincidence … they both happen to begin with the letter "E". :biggrin:

(partly for that reason, some books use a curly E for emf)
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top