Emitter follower question (transistors)

  • Thread starter Thread starter Simfish
  • Start date Start date
  • Tags Tags
    Transistors
Click For Summary
SUMMARY

The discussion focuses on calculating the input and output impedance of an emitter follower circuit using a transistor with a current gain (β) of 100 and an emitter resistor (R_E) of 1000 Ω. The input impedance with an unloaded output is determined to be R_E multiplied by 100, resulting in 100,000 Ω. When connected to a source with an output impedance of 500 Ω, the output impedance of the circuit is calculated as (500 + 100,000) / 100, yielding 1,005 Ω. Finally, with a 100 Ω load at the output, the input impedance is computed as 100 times the parallel combination of R_E and the load, which is 1000 || 100.

PREREQUISITES
  • Understanding of transistor operation and characteristics, specifically emitter followers.
  • Knowledge of impedance calculations in electrical circuits.
  • Familiarity with the concept of current gain (β) in transistors.
  • Ability to perform parallel resistor calculations.
NEXT STEPS
  • Study the detailed operation of common collector amplifiers.
  • Learn about the effects of varying load impedance on circuit performance.
  • Explore advanced transistor models and their applications in amplifier design.
  • Investigate the impact of source impedance on signal integrity in electronic circuits.
USEFUL FOR

Electrical engineering students, hobbyists designing amplifier circuits, and professionals working with analog electronics will benefit from this discussion.

Simfish
Gold Member
Messages
811
Reaction score
2

Homework Statement


3. An emitter-follower is built using a transistor with β = 100 and R_E =
1000 Ω . (a) Whatʼs the input impedance with unloaded output? Now
suppose the input is connected to a source having output impedance
500 Ω . Whatʼs the output impedance of the circuit? (c) Remove the
source. Now, if a load 100 Ω is at the output, whatʼs the input
impedance?

Here, R_E/I_E refers to the output part of the transistor, and R_B/I_E refers to the input part.

(a)
β = I_C/I_B, so I_C = 100I_B.

So with unloaded output, should the input impedance be R_E*100?

(b)
If input is connected to a source with output impedance 500Ω, does that imply that the input impedance is 500+R_E*100? And that the output impedance is, thus, (500+R_E*100)/100?

(c)
100Ω output, so does that imply that the input impedance is 100(1000||100)? I believe that 1000||100 should be the total output impedance of R_E (since the load means that they're in parallel), and the input impedance is 100 times that, right?

Have I done things correctly? Am I missing anything?
 
Last edited:
Physics news on Phys.org
The http://en.wikipedia.org/wiki/Common_collector" has a nice summary.
 
Last edited by a moderator:
Yeah, I've already read it. I'm just not sure if I'm missing anything here.
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
14K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
4
Views
12K
  • · Replies 7 ·
Replies
7
Views
13K
  • · Replies 25 ·
Replies
25
Views
10K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 59 ·
2
Replies
59
Views
7K
Replies
5
Views
6K