Energy and Entropy from P-V Diagram

AI Thread Summary
The discussion focuses on solving a physics problem involving an ideal monatomic gas undergoing a thermodynamic cycle. Key points include calculating work done by the gas, changes in internal energy, and entropy during specific transitions in the cycle. The user initially struggles with parts B and D, lacking necessary variables to apply relevant equations. Guidance is provided to express temperature changes in terms of pressure and volume, which ultimately helps the user solve the problem quickly. The conversation highlights the importance of understanding relationships between thermodynamic variables to facilitate problem-solving.
Rapier
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Homework Statement


An ideal monatomic gas is taken through the above cycle where p1= 2 X 105 Pa and V1 = 5 cm3. During the cycle both the pressure and volume will change such that p2 = 2 p1 and V2 = 4 V1.

a) How much work is done by the gas in going from state a to state c along path abc?
Wabc = 3 J
OK

b) What is the change in internal energy in going from b to c?
Ubc= J

c) What is the change in internal energy during the complete cycle?
UTOT = 0 J
OK

d) What is the change in entropy per mole of gas in going from b to c?
ΔSbc = J/K

e) What is the change in entropy per mole during the complete cycle?
ΔSTOT= 0 J/K
OK

I am having problems with Parts B and D.

Homework Equations


PV=NRT
Q = nCvdt


The Attempt at a Solution



I only have P and V. I cannot use the Ideal Gas Law to calculate n or T because I have two unknowns. I cannot use my Heat Equations because I am still missing n and T. I'm just stuck. If I can calculate B, I think I can get D...I just don't see any way to calculate the Heat in part B. HELP!

Thanks.
 

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Rapier said:
b) What is the change in internal energy in going from b to c?
Ubc= J
Use: ΔU = nCvΔT = n(3R/2)ΔT

Since PV = nRT, you can express ΔT in terms of ΔP and V (V is constant).

d) What is the change in entropy per mole of gas in going from b to c?
ΔSbc = J/K
Use: dS = dQ/T. What is the heat flow in terms of dT and Cv? Integrate that to get ΔS.

AM
 
Andrew Mason said:
Use: ΔU = nCvΔT = n(3R/2)ΔT

Since PV = nRT, you can express ΔT in terms of ΔP and V (V is constant).

Use: dS = dQ/T. What is the heat flow in terms of dT and Cv? Integrate that to get ΔS.

I can't believe I didn't see that. Once I read "express ΔT in terms of ΔP and V" it all fell together. It took me less than 2 minutes to solve the problems. Thanks! :)
 
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