Energy conservation and e = mc^2

AI Thread Summary
The discussion clarifies the distinction between kinetic energy (KE) and the energy-mass equivalence expressed in E=mc². Kinetic energy is calculated using the formula KE = 1/2 mv², which relates mass and velocity, while E=mc² represents the intrinsic rest energy of a mass, independent of its motion. The constant c in E=mc² refers to the speed of light, not a variable velocity like in the kinetic energy equation. The two equations describe different types of energy, with E=mc² linking mass to energy as a fundamental principle. Understanding this difference is essential for grasping concepts in energy conservation and relativity.
iommi0028
Messages
2
Reaction score
0
If Kinetic Energy is mv²/2 how come E=mc² is a valid equation.. wouldn't it have to be divided by two also because c represents a velocity? Thanks for any help.
 
Physics news on Phys.org
the equation e = mc^2 is a fundamental relation between mass and energy. A particle of mass m has an "intrinsic rest energy" Eo given by Eo = mc^2

im not 100% on the way that they derived k = 1/2 mv^2 but i do know that its only used when relating mass velocity and kinetic energy.

the Eo is the energy a mass has with no relation to velocity or position. the c is a velocity but its a relation to the speed of light your making, in 1/2 mv^2 the velocity your relating there is that of the particle of mass m.

basically the energies in the 2 equations are not the same, and in one your relating the speed of the mass, and in the other your relating a mass to a constant [the speed of light]

hope that helps.
 
the 1/2mv^2 is derived by integrating the force ma over a certain distance:
<br /> \int_{a}^{b}ma dx<br />
 
Last edited:
hey thanks that really cleared things up
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Back
Top