Energy of proton moving fast (special relativity)

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SUMMARY

The discussion centers on calculating the energy of a proton moving at relativistic speeds across the Milky Way, which is approximately 10^5 meters wide. The participant struggles with applying the special relativity equations, specifically L = L0 Sqrt[1-(v/c)^2] and t = t0 Sqrt[1-(v/c)^2], leading to an incorrect conclusion that the proton's energy is infinite. The key insight is that the distance measured by the proton is not the same as that measured in the galaxy's reference frame, necessitating the use of Lorentz transformations to accurately relate the two frames of reference.

PREREQUISITES
  • Understanding of special relativity concepts, particularly Lorentz transformations.
  • Familiarity with the equations L = L0 Sqrt[1-(v/c)^2] and t = t0 Sqrt[1-(v/c)^2].
  • Knowledge of relativistic energy calculations.
  • Basic grasp of reference frames in physics.
NEXT STEPS
  • Study the application of Lorentz transformations in special relativity.
  • Learn how to calculate relativistic energy using E = mc^2 and its modifications for high-speed particles.
  • Explore the concept of time dilation and length contraction in different reference frames.
  • Practice solving problems involving relativistic speeds and their effects on energy and time measurements.
USEFUL FOR

Students of physics, particularly those studying special relativity, as well as educators and anyone interested in understanding the implications of relativistic motion on energy and time measurements.

FatheadVT
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Homework Statement


Given: in its own reference frame a proton takes 5 minutes to cross the Milky Way (10^5 meters).
(a) What is the approximate energy of the proton?
(b) About how long would the proton take to cross the galaxy as measured by an observer in the galaxy's reference frame?

Homework Equations


All those equations for special relativity I imagine.
L = L0 Sqrt[1-(v/c)^2]
t = t0 Sqrt[1-(v/c)^2]

The Attempt at a Solution


So I keep doing this over and over again, getting a wrong answer. The way I approach it is this: I think L is the distance as measured by the proton when crossing the galaxy, and t is the time the proton measures (5 minutes). Since v is the same in both reference frames (how fast the galaxy thinks the proton is moving and how fast the proton thinks the galaxy is moving) I can say that L/t = v. Using those equations I do it all out and find that v = c. Not very useful when I plug it into my equations for energy and find the proton has infinite energy. Where am I going wrong?

Also, I think this should be doable without the Lorentz transformations.
 
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I'm not very confident about relativity, but I think you may have an error in assuming the galaxy is 10^5 meters wide from the point of view of the proton. I expect you have to use one of the formulas to transform this to the proton's point of view. Or else transform the 5 minutes to the galaxy's point of view. Before calculating the velocity. Of course you can't do that numerically, so you'll have an expression with a v in it rather than a number. Hopefully after the next step - find v - you will be able to get the two v's together somehow and solve for v.
 

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