Energy required to strip final electron

AI Thread Summary
To find the energy required to remove the final electron from a doubly ionized lithium (Li2+) atom, the relevant formula is En = -z^2/n^2, where z is the atomic number and n is the principal quantum number. For Li2+, the atomic number z is 3, and since there is one remaining electron, n is 1. The initial assumption that z could be treated as 1 like hydrogen is incorrect. Clarification on the formula and conversion to electron-volts is necessary for accurate calculations. Understanding the correct application of these principles is crucial for solving the problem.
BobMcPhysics
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Homework Statement



Find the energy in electron-volts required to remove the remaining electron from a doubly ionized lithium (Li2+) atom.

Homework Equations



En=-z^2/n^2

The Attempt at a Solution



I thought z was 3 for lithium, that doesn't work. I thought since there was only one remaining electron you could treat it like Hydrogen and use z (or E1) = -13.6 eV but that's not right either. Clearly the n in the denominator is 1 from above.

I'm lost!
 
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