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## Homework Statement

A 12.0-V battery is connected to a capacitor, resulting in 54.0 μC of charge stored on the capacitor. How much energy is stored in the capacitor?

## Homework Equations

1/2CV^2

## The Attempt at a Solution

At first this problem looks to be easy for me but somehow I get a complete different answer than the back of the book.

I plugged in all the variables and solved and got 3.88 x 10^-4 J

1/2(5.4x10^-6)(12)^2

The answer I get in the back of the book is 3.24 x 10^-4 J

Can someone please explain to me what I am doing wrong?

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