Energy to heat water in a stem engine

Thread starter asasin114
Start date Jan 15, 2011
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Energy Engine Heat Stem Water

AI Thread Summary

To calculate the energy required to heat 2.50 liters of water from 100°C to 250°C in a steam engine, the formula Q=mcΔT is used, where Q is the heat energy, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature. Given that the mass of the water is 2500 grams and the specific heat capacity of water is approximately 4.19 joules per gram per degree Celsius, the change in temperature (ΔT) is 150°C. By substituting these values into the equation, the necessary energy can be calculated. Understanding this formula is crucial for solving the problem effectively. The discussion emphasizes the importance of grasping the relationship between mass, specific heat, and temperature change in thermal energy calculations.

Jan 15, 2011

asasin114

Homework Statement

Using the conversion rate of 4.19 joules per calorie, how much energy is necessary to heat 2.50 liters (2500 grams) of water in a steam engine from 100 Celsius Degrees to 250 Celsius Degrees?

Homework Equations

The Attempt at a Solution

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Jan 15, 2011

rock.freak667

Homework Helper

Do you know the formula Q=mcΔT = mass*specific heat capacity*change in temperature ?

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