Entropy of the river due to coal heating

AI Thread Summary
To calculate gamma (Cp/Cv) for the gas, start by applying the first law of thermodynamics, which relates heat added (Q), work done (W), and change in internal energy (ΔU). Given that 980 J of heat is added and 234 J of work is done, ΔU can be calculated as ΔU = Q - W. The change in internal energy is also related to Cv and the change in temperature (ΔT). By determining Cp using the relationship Cv = Cp - nR and substituting the values, gamma can be calculated. Understanding these relationships is crucial for solving the problem effectively.
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Gamma (Cp/Cv) of a gas

Homework Statement



An experimenter adds 980 J of heat to 1.75 mols of an ideal gas to heat it from 10.0 C to 25.0 C at constant pressure. The gas does 234 J of work during the expansion. Calculate gamma (Cp/Cv) for the gas.

Homework Equations



Cv=Cp-nR
Gamma =Cp/Cv

The Attempt at a Solution



No idea where to start. I found other ratios between the variables but I'm still confused. Do i have to use Q or delta Q?
 
Last edited:
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idkididk said:

Homework Statement



An experimenter adds 980 J of heat to 1.75 mols of an ideal gas to heat it from 10.0 C to 25.0 C at constant pressure. The gas does 234 J of work during the expansion. Calculate gamma (Cp/Cv) for the gas.

Homework Equations



Cv=Cp-nR
Gamma =Cp/Cv

The Attempt at a Solution



No idea where to start. I found other ratios between the variables but I'm still confused. Do i have to use Q or delta Q?
Apply the first law. Assume that it is a quasi-static process. What is ΔU? How does ΔU relate to Cv and ΔT? What is the difference between Cv and Cp? Answer all those questions and you will be able to determine Cp.

AM
 
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