Equation for airtime given velocity?

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Homework Help Overview

The problem involves determining the airtime of a mass thrown vertically upward in a vacuum on Earth, starting from an initial height of 0 m. The original poster seeks to create an equation that relates the initial velocity to the time spent in the air, using kinematic principles.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to apply standard kinematics equations but expresses uncertainty about how to derive the airtime from them. Participants discuss the significance of displacement in the context of the problem and explore the implications of the mass returning to its initial position.

Discussion Status

The discussion is ongoing, with participants providing insights into the application of the kinematic equation. Some guidance has been offered regarding the treatment of displacement, and there is an exploration of the algebraic manipulation required to solve the equation.

Contextual Notes

The original poster mentions being sleep-deprived and emphasizes that this is part of a larger lab question, indicating potential constraints on their current understanding or focus.

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Equation for air time given velocity?

Homework Statement


Given a certain velocity going straight up in a vacuum on Earth from y = 0 m, how long does a mass remain in the air? Create an equation.
(So, for example, if you throw a baseball up at 20 m/second, how long will it take for it to fall back to your hand?)


Homework Equations


Unsure...d = v*t + 1/2at^2?


The Attempt at a Solution


I know that this should be really elementary, but I must be really sleep-deprived because I'm just not seeing how to extrapolate it from my standard kinematics equations.
For the record, this isn't the whole question, just the part of a lab I'm hung up on...so please don't think I'm trying to get you guys to do my job for me.
 
Last edited:
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You have the correct equation. Just consider this: the d is a vector. It represents the "displacement," or the straight line distance between the initial and final positions of the mass.

Now assume that the mass falls back to the its initial position. What is d =?
 
Oh. Okay. So for the sample;
0 = 20*t + 1/2(-9.8)t^2
0 = 20t + -4.9t^2
0 = 20t - -4.9t^2...
...apply Quadratic Formula at this point?
 
Last edited:
No, it's easier than that. Subtract 20t from both sides. then...
 

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