Equation for solving the coefficient of Kinetic friction HELP?

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To find the coefficient of kinetic friction for a 9 kg block being pulled at a constant velocity with a tension of 5.2 N, the net force is zero, indicating that friction equals the pulling force. The equation for the coefficient of kinetic friction (uk) is derived from the ratio of the frictional force to the normal force. The normal force in this case equals the weight of the block, calculated as 88.2 N (9 kg multiplied by 9.8 m/s²). Thus, the coefficient of kinetic friction is determined by dividing the frictional force (5.2 N) by the normal force (88.2 N), resulting in approximately 0.059. Understanding that the block moves at a constant speed helps clarify that the forces are balanced, guiding the calculation of uk.
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Equation for solving the coefficient of Kinetic friction HELP??

Problem: A cable attached to a block of mass 9 kg pulls the block along a horizontal floor at a constant velocity. If the tension in the cable is 5.2 N, what is the coefficient of kinetic friction between the block and the floor?




Questions:I have tried to solve this but i really don't know where to begin.
Whats the equation to calculate the coefficient of Kinetic Friction?


Attempt: ok i know Mass= Friction/Gravity and gravity is 9.8,
u=friction(k)/Normal force


Fg= 9kg* (9.8)= 88.2 kg

Ef=Ma = 5.2n +Ffk= 9kg * o m/s^2 = Ffk=-5.2 n

[uk]= 5.2/100 = 0.052 m/s^2

is this right? so confused


i really just don't have any idea about the the equation...HELP??
 
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If the block is moving at a constant speed then there must be no net force on the block. That is the friction cancels out the force pulling it. Take a look at the following page about friction and have another go.

http://hyperphysics.phy-astr.gsu.edu/hbase/frict2.html
 

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