1. The problem statement, all variables and given/known data A uniform rod AB of length 5 m and weight 50 N is pivoted at A and held in equilibrium by a rope as shown. A load of 100 N hangs from the rod at a distance x from A. If the breaking strength of the rope is 50 N, find the maximum value of X. 2. Relevant equations τnet = 0, τ = Fr⊥ 3. The attempt at a solution The solution I came up with is τ = [50(sin(37))*5(cos(37)) - (50*(5(cos(37)))/2) - (100(cos(37)x)) = 0, which gave me x = 0.29 m. I just wanted to verify that I'm doing this correctly.