Equilibrium applications of Newton's law of motion

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A supertanker with a mass of 1.72 * 10^8 kg is moving at a constant velocity, with its engines generating a forward thrust of 5.52 * 10^4 N. Since the velocity is constant, the acceleration is zero, leading to the conclusion that the resistive force exerted by the water is equal to the thrust, calculated as 5.52 * 10^4 N. For the upward buoyant force, it is determined that this force is equivalent to the weight of the displaced fluid, which can be calculated using the formula U = mg, where m is the mass of the tanker and g is the acceleration due to gravity. The discussion emphasizes understanding the relationship between thrust, resistive forces, and buoyancy in the context of Newton's laws of motion.
pookisantoki
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A supertanker with the mass of 1.72 *10^8 kg is moving with a constant velocity. Its engines generate a forward thrust of 5.52*10^4 N. Determine (a) the magnitude of the resistive force exerted on the tanker by the water and (b) the magnitude of the upward buoyant force exerted on the tanker by the water.

I honestly don't know how to do this at all but from the given infor. I thought I could find the sum of forces by M *A but then since it's constant velocity, A would be zero making sume of forces 0. Since it is constant velocity I thought i could use the constant velocity formulas but wasnt sure which one to use since I'm only give mass. I don't even know what kind of force a forward thrust would be considered as... I am so lost please help!
 
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If you are lost then let's take it in steps.

The engine produces a thrust (force) of 5.52*104 N (FE)

Let's call the resistive force Ff.


So we know the resultant of these two is ma. Now we have an equation ma=FE-Ff.


But we are told the velocity is constant, which tells you that a=0. So can you get the resistive force now?
 
THANK YOU! so I solved it 0=5.52 *10^4-x
x=55200
then for part b. The bouyance force is the force that goes up...would be considered same as normal force? and the answer is the same as the mass * g??
 
pookisantoki said:
THANK YOU! so I solved it 0=5.52 *10^4-x
x=55200
then for part b. The bouyance force is the force that goes up...would be considered same as normal force? and the answer is the same as the mass * g??

I believe that is how it should be done. Although upthrust=weight of fluid displaced = mg =ρVg.

But they didn't give you V=volume of water displaced. So U=mg will work.
 
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