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dumbengineer
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[SOLVED] Equilibrium of a particle - hibbeler , help please
Hi all
I was surfing the net looking for a physics / mechanic forum and thank god i found this.
I have problem with solving Equilibrium problems, hopefully you guys and girls would help me out.
1) Question. ( this is problem 3-1 , in engineering mechanic statics , 11th edition hibbeler)
- Determine the magnitudes of F1 and F2 so that the particle is in equilibrium
Given : F1 = 500N , θ1 = 45deg and θ2 = 30 deg
2) this is how far i went.
ΣFx = F1 cos θ1 + F2 cos θ2 - F = 0
ΣFy = F1 sin θ1 -F2 sin θ2 = 0
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ΣFx = F1 cos 45 + F2 cos 30 - 500 = 0
ΣFy = F1 sin 45 -F2 sin 30 = 0 -> f1sin 45 = f2sin 30
so , f1 cos 45 + f1sin 45 - 500 = 0
f1 cos 45 + f1 sin 45 = 500
f1 1.41 = 500
500 / 1.41 = 354.60
well that answer is wrong , i know that f1 = 259 and f2 = 366 those are the correct answers
any help guys
thanks in advance
Hi all
I was surfing the net looking for a physics / mechanic forum and thank god i found this.
I have problem with solving Equilibrium problems, hopefully you guys and girls would help me out.
1) Question. ( this is problem 3-1 , in engineering mechanic statics , 11th edition hibbeler)
- Determine the magnitudes of F1 and F2 so that the particle is in equilibrium
Given : F1 = 500N , θ1 = 45deg and θ2 = 30 deg
2) this is how far i went.
ΣFx = F1 cos θ1 + F2 cos θ2 - F = 0
ΣFy = F1 sin θ1 -F2 sin θ2 = 0
-
ΣFx = F1 cos 45 + F2 cos 30 - 500 = 0
ΣFy = F1 sin 45 -F2 sin 30 = 0 -> f1sin 45 = f2sin 30
so , f1 cos 45 + f1sin 45 - 500 = 0
f1 cos 45 + f1 sin 45 = 500
f1 1.41 = 500
500 / 1.41 = 354.60
well that answer is wrong , i know that f1 = 259 and f2 = 366 those are the correct answers
any help guys
thanks in advance