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Equilibrium Problem

  1. Jul 17, 2006 #1
    As you can see in the attachmen, I'm supposed to find the equilibriant force and the force from the left side.

    So is it something like this:

    Fx = 0,

    Fh + 200cos20-100cos30=0
    Fh = -101.33N

    Fy = 0
    Fv + 200sin20 + 100sin30 = 0
    Fv = -118N

    But I get stuck on the rest. Can someone help me out please?
     

    Attached Files:

  2. jcsd
  3. Jul 17, 2006 #2

    Office_Shredder

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    I'm a bit confused here.... exactly what are you trying to solve for?
     
  4. Jul 17, 2006 #3
    Actually, I think I figured it out but are the vertical and horizontal forces correct? Or do the Fh and Fv should cancel out
     
  5. Jul 17, 2006 #4
    I'm supposed to find the equilibriant force on the diagram I posted (see attachments)
     
  6. Jul 17, 2006 #5
    the force that give you equilibrium is 155.55N and its direction is 49.35 degress to the horizontal
     
  7. Jul 17, 2006 #6
    uhmm...thanks for telling me the answer, but it's useless if I don't know how to get the answer =(
     
  8. Jul 17, 2006 #7
    -101.33 + (theforce)cosA = 0
    -188 + (theforce)sinA = 0

    tanA = -188 / -101.33


    therefore A = 49.35 degrees to the horizontal
     
    Last edited: Jul 17, 2006
  9. Jul 17, 2006 #8
    if you need further explaination let me know
     
  10. Jul 17, 2006 #9
    Wait how did you get -188 for the vertical?
     
  11. Jul 17, 2006 #10
    nvm I think you meant 118. if you divided 188, you get 61 degrees.
     
  12. Jul 17, 2006 #11
    well

    -188 +FsinA = 0
    is the same as writing
    -188 +Fcos(90-A) = 0

    since its sin it means it is the verticle

    but this does not mean that Fy will always be the verticle if you in a situation where Fx has to be sin0 then fx will be the verticle and it would be 101.33/118
    instead of the other way around

    if your still not 100% percent clear i ll draw a picture for you, its quite hard to explain without pictures
     
  13. Jul 17, 2006 #12
    yes i meant 118
    sorry about that
     
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