Equivalent Resistance in series circuit

AI Thread Summary
The discussion revolves around calculating the equivalent resistance and current in a series circuit with three resistors (7.0 Ω, 12 Ω, and 16 Ω) connected to a 9.0 V battery. The total equivalent resistance is found by summing the individual resistances, resulting in 35 Ω. The current through each resistor is the same, calculated using the formula I = V/Rs, yielding a current of 0.26 A. For power delivered to the 16 Ω resistor, the formula P = I^2 * R is used. The key takeaway is that in a series circuit, the current remains constant across all resistors.
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Homework Statement


Three resistors with values of 7.0 Omega, 12 Omega, and 16 Omega are connected in series in a circuit with a 9.0 V battery.
a) What is the total equivalent resistance?
b) What is the current in each resistor?
c) At what rate is energy delivered to the 16 Omega resistor?

Homework Equations



I= V/Rs
P = V^2 /R ?

The Attempt at a Solution


I got "a" but missed "b". i used the first equation and got .26 then divided that by 3 but I guess that's not what you do. For "c" i really have no clue. help!
 
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In series connection the current is the same in all the resistances.
For "c", the power can also be written as P = I^2*R.
 
so for b the answer would be just .26 and not divide by 3?
 
Yes.
 
thanks!
 

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