Error function (defined on the whole complex plane) is entire

julypraise
Messages
104
Reaction score
0

Homework Statement


The wiki page says that error function \mbox{erf}(z) = \int_{0}^{z} e^{-t^{2}} dt is entire. But I cannot find anywhere its proof. Could you give me some stcratch proof of this?


Homework Equations





The Attempt at a Solution


I've tried to use Fundamental Theorem of Calculus but as it is the line integral I couldn't use it.
 
Physics news on Phys.org
You can just expand the integrand as a Taylor series, integrate by terms (since everything is finite) and then convince yourself that the resulting series converges everywhere.
 
clamtrox said:
You can just expand the integrand as a Taylor series, integrate by terms (since everything is finite) and then convince yourself that the resulting series converges everywhere.

Ah.. frankly I'm not sure of how to expand by Taylor series... Is it by using Cauchy's Theorem? Could you give me any reference textbook where I can look up the theorem for this Taylor series expansion?
 
julypraise said:
Ah.. frankly I'm not sure of how to expand by Taylor series... Is it by using Cauchy's Theorem? Could you give me any reference textbook where I can look up the theorem for this Taylor series expansion?

If you pick any analysis textbook at random, the odds of it containing a chapter on Taylor series is very very high. The extension to complex variables is straightforward.

You can also proceed by doing the standard proof that the function is holomorphic, by using the Cauchy-Riemann equations, but then you also have to consider whether the function has an analytic continuation to the entire complex plane. For example logarithm is holomorphic in its domain, but is not an entire function. That's why the Taylor series route is more straightforward: you can show that the series converges everywhere, which automatically shows you that the function is entire.
 
julypraise said:

Homework Statement


The wiki page says that error function \mbox{erf}(z) = \int_{0}^{z} e^{-t^{2}} dt is entire. But I cannot find anywhere its proof. Could you give me some stcratch proof of this?


Homework Equations





The Attempt at a Solution


I've tried to use Fundamental Theorem of Calculus but as it is the line integral I couldn't use it.

I don't see what's wrong with just differentiating it, showing the derivative is analytic throughout the complex plane, then concluding it's entire. That is, since

\frac{d}{dz} \text{erf}(z)=e^{-z^2}

and e^{-z^2} is analytic, thus the error function is entire.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top