- #1
shaan_aragorn
- 43
- 0
escape velocity derivation
The problem is thus:
The acceleration of a satellite is given by -gR^2/r^2 where R= radius of Earth and r = distance of satellite from center of the earth. Find escape velocity.
Now I have read the solution to this problem and in it the author at one point has integrated v dv = -gR^2/r^2 with the upper limit for vdv being 0 and the lower limit being Ve(Escape velocity).
Now my problem is, why is 0 the upper limit and Ve the lower limit if in magnitude Ve>0?
The problem is thus:
The acceleration of a satellite is given by -gR^2/r^2 where R= radius of Earth and r = distance of satellite from center of the earth. Find escape velocity.
Now I have read the solution to this problem and in it the author at one point has integrated v dv = -gR^2/r^2 with the upper limit for vdv being 0 and the lower limit being Ve(Escape velocity).
Now my problem is, why is 0 the upper limit and Ve the lower limit if in magnitude Ve>0?
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