• Support PF! Buy your school textbooks, materials and every day products Here!

Escape velocity from asteroid

  • Thread starter gagge78
  • Start date
  • #1
2
0

Homework Statement


We assume an asteroid with density similar to earth. An astronaut performs a spot jump of 1 meter. Which is the maximum radius of the asteroid in order to escape the astronaut from the asteroid?

Homework Equations


Vesc=√2GM/R=R√8ΠGρ/3


The Attempt at a Solution


Vesc,earth/Vesc,ast=Rearth/Rast→ Rast=Rearth Vesc,ast/Vesc,earth
So the values of Rearth and Vesc,earth are known i need one more equation in order to calculate Vesc,ast which will be the minimum velocity that is necessary to reach 1 meter above the ground. So i am stuck!!!

Homework Statement





Homework Equations





The Attempt at a Solution

 

Answers and Replies

  • #2
Andrew Mason
Science Advisor
Homework Helper
7,566
330
I am having difficulty understanding how a person doing a jump of only 1 m. from the asteroid can possibly escape. Can you give us the exact wording of the question?

AM
 
  • #3
2
0
Also for me is difficult. But as i can understand speaking for an imaginary asteroid we try to find the necessary radius for which the escape velocity is equal with the begging velocity that we need for a jump of 1 meter (according to the energy conservation: v0=√2gh).
 
  • #4
Redbelly98
Staff Emeritus
Science Advisor
Homework Helper
Insights Author
12,098
129
I suspect the wording of the question is different than what is posted here. Are you translating from a language other than English?

A velocity that results in a jump of 1 meter height can never be equal to the escape velocity, which produces a jump of infinite height. This is a simple logical fact. Perhaps you mean the velocity that would produce a 1 m jump height under different conditions -- but we need to know what those conditions are.

p.s. Welcome to Physics Forums.
 
  • #5
Andrew Mason
Science Advisor
Homework Helper
7,566
330
Also for me is difficult. But as i can understand speaking for an imaginary asteroid we try to find the necessary radius for which the escape velocity is equal with the begging velocity that we need for a jump of 1 meter (according to the energy conservation: v0=√2gh).
There appears to be language/translation problem here.

Is the 1m. the height of the jump of the person on the earth surface? Do you want to know the radius of the asteroid such that the energy used in such a jump on the earth would provide the escape energy from the asteroid?

If that is the question, write out the expression for r, the asteriod radius, in terms of the radius, R, and density, ρ, of the earth (ρ = Mearth/4∏R^3/3; Masteroid = ρ4∏r^3/3). Then use that in the equation for escape velocity.

AM
 

Related Threads on Escape velocity from asteroid

Replies
4
Views
2K
  • Last Post
Replies
5
Views
238
  • Last Post
Replies
7
Views
1K
  • Last Post
Replies
3
Views
7K
Replies
4
Views
4K
Replies
4
Views
7K
Replies
2
Views
2K
Replies
3
Views
5K
Replies
16
Views
3K
Replies
6
Views
3K
Top