Estimate Temperature of Mars Using Sun's Heat

  • Thread starter Thread starter Manda_24
  • Start date Start date
  • Tags Tags
    Mars Temperature
AI Thread Summary
To estimate the temperature of Mars, one must consider it as a perfect blackbody receiving heat solely from the Sun. The discussion highlights the need to calculate the power Mars receives and the power it must emit to determine its temperature. The relevant equation for radiation, Iemitted = Q/t = eA(sigma)T^4, is essential for this calculation, where A represents the surface area receiving sunlight. Clarification is provided on the importance of understanding which area of Mars absorbs solar energy versus the area that emits energy into space. Ultimately, applying these principles will lead to an accurate estimation of Mars' temperature.
Manda_24
Messages
9
Reaction score
0

Homework Statement


Estimate the temperature of Mars. Assume Mars acts as a perfect blackbody and the only heat input comes from the Sun (use necessary values from appendix)


Homework Equations





The Attempt at a Solution



I was doing so well until I got to this question on my homework.
I tried this: (pi)(rmars)2 / 4(pi)rsun2

for the radius of Mars my book says 6370 km and the sun 6.95e5 km
 
Physics news on Phys.org
Thats just one small step in the answer.

First think about what the question means:
How much power does Mars recv from the sun ?
How much power must it emit (and why)
Therefore what temperature must it be?
 
We finally talked about this a little in class today, I think. The teacher put up an equation for radiation.
Iemitted=Q/t=eA(sigma)T4

Is this part of what I need to use to finish the question? I know what sigma is and e but I don't know what A is.
 
This is the power emitted by a surface of area A at temperature T

Careful - what area of Mars receives energy from the sun and what area emits energy into space?
 
Thanks for your help, I finally got it
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top