Estimating electric field strength

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To estimate the electric field strength at point A, the formula E = -dV/ds is applied. The potential difference is calculated as 12.5V over a distance of 0.00625m, yielding an initial electric field strength of 2000V/m. Since point A is positioned 1/8 of the way from the left side of a 5cm grid, the effective distance is adjusted by dividing the strength by 4, resulting in a final strength of 500V/m. The direction of the electric field is confirmed to be to the left, as it points towards decreasing potential. This analysis effectively demonstrates the method for estimating electric field strength and direction.
Linus Pauling
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1. Estimate the electric field (strength and direction) at the point A.

5cmx5cm gridL
30.P49.jpg




2. E = -dV/ds



3. I had four options, each a combination of 500 or 1000V/m for the E field strength and then left or right for the direction. I knew it must be to the left because the field points in the direction of decreasing potential, but how was the strength obtained (the answer is 500V/m)?

I did E = dV/ds = 12.5V/.00625m = 2000V/m, because point A is 1/8(5cm) from the left side of the grid...
 
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and then I divided by 4 because there are 4 boxes (1/2 of 5cm) between the left side and point A. So 2000V/m/4 = 500V/m.
 

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