Estimating Energy Generated by Niagara Falls

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To estimate the energy generated by water falling over Niagara Falls in five days, the calculation begins with the height of 150 meters and a water flow rate of 104 m³/sec. The total time for the five days is calculated as 4,320,000 seconds. The potential energy is determined using the formula P = W/t, where W is the work done, calculated as mgh. The mass can be found by converting the flow rate into mass using the density of water, approximately 1000 kg/m³. This method provides a comprehensive approach to estimating the energy produced by the falls.
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Homework Statement


Estimate E generated by water falling over Niagara falls in 5 day.
Height = 150m
Water flow =104m3/sec
t=5x24x60x60=4320000sec


Homework Equations


P=W/t
mgh=mv2/2


The Attempt at a Solution


Work=mgh=m(9.8)(150)
Time=432000seconds
P=m(1470)/4320000

I just don't know how to convert 104m3/sec into a mass
 
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The density of water is ~1000kgm^{-3}.

You can use this to work out the mass flowing per second.
 
Alright niceee thanks for the help :)
 
No problemo :)
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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