Estimating Time to Reach Terminal Speed Using Drag & Unit Analysis

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A marble falling through a fluid experiences a drag force proportional to its velocity, leading to a terminal speed defined by v=(mg)/A. To estimate the time to reach this terminal speed, dimensional analysis can be applied using the parameters A, g, and m. The characteristic time, τ, can be derived from the relationship between mass, drag coefficient, and gravitational acceleration. The hint suggests that g is essential for constructing this time estimate, indicating a deeper connection between terminal velocity and gravitational effects. Understanding this relationship is crucial for accurately calculating the time to terminal speed.
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Homework Statement


A marble of mass m falls through a fluid and is subject to the drag force F=-Av, where v is the velocity of the marble. The marble will reach a terminal speed given by v=(mg)/A. Use dimensional analysis to estimate how long it will take to reach the terminal speed. (Hint: A characteristic "time" can be constructed from A, g, and m.)

The Attempt at a Solution


The units on A are F/v= (kg/s).
The units on g are m/(s^2).
The units on m are kg.

However, g is the only value with meters, so I don't know how I'm supposed to combine them and get time, unless it's just m/A, but then why did the book give a hint about using g? Thanks for the help.
 
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Jstew said:

Homework Statement


A marble of mass m falls through a fluid and is subject to the drag force F=-Av, where v is the velocity of the marble. The marble will reach a terminal speed given by v=(mg)/A. Use dimensional analysis to estimate how long it will take to reach the terminal speed. (Hint: A characteristic "time" can be constructed from A, g, and m.)

The Attempt at a Solution


The units on A are F/v= (kg/s).
The units on g are m/(s^2).
The units on m are kg.

However, g is the only value with meters, so I don't know how I'm supposed to combine them and get time, unless it's just m/A, but then why did the book give a hint about using g? Thanks for the help.
Yeah, the characteristic time, \tau, is, as you astutely noted, m/A. But this is derived from the terminal velocity (a function of m, g, and A) and the acceleration of gravity, g. So use dimensional analysis to find \tau by combining ,in some fashion, terminal velocity and g.
 
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