Euler Lagrange equations with viscous dissipation

Dustinsfl
Messages
2,217
Reaction score
5

Homework Statement


The system can pivot at point O and I am taking small angle approximations.
I am trying to determine the Lagrangian, ##\mathcal{L} = T - U## for the following system:
2nh6RzK.png


Homework Equations


E-L equation with dissipation: ##\frac{\partial\mathcal{L}}{\partial q_i} - \frac{d}{dt}\frac{\partial\mathcal{L}}{\partial\dot{q}_i} + \frac{\partial D}{\partial\dot{q}_j} = 0##

The Attempt at a Solution


I am going to use the generalized coordinate theta.

For the circular mass, I have the potential energy to be ##mg(1-\cos(\theta)) = \frac{mg\theta^2}{2}## and the kinetic energy is ##\frac{1}{2}J\dot{\theta}^2## where J is the mass moment of inertia. The potential energy of the spring is ##\frac{1}{2}kx^2##, and the dissipative energy is ##D = c\frac{\dot{x}^2}{2}##.

Before I convert the xs to thetas am I missing a kinetic or potential energy?
 
Physics news on Phys.org
Don't think you are missing anything. I do worry about the potential energy signs.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top