Euler's rule or Non-homogenous method?

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Homework Statement


x^2 y' + xy + 5x^5=0

Homework Equations


no starting conditions


The Attempt at a Solution


cannot figure out how to do this. Euler's equations methods have no pure x terms, and the non-homogenous methods have some kind of separable thing, where the x terms neatly land up on RHs and y terms on LHS. But what do i do with this? Is it the polynomial expansion or maybe some kind of taylor series?
 
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U can divide by "x" (assuming x different from 0) and then write the resulting eqn as

[tex](xy)'=-5x^{4}[/tex]

Integrate both terms and then see what you get.

Daniel.
 
I think dextercioby missed a term.

Start by putting in the form y' + y*(1/x) = -5x^3

Next, your integrating factor is p = e^[integral(1/x)dx] = e^(lnx) = x

Continue...
 
Stevecgz said:
I think dextercioby missed a term.

Start by putting in the form y' + y*(1/x) = -5x^3

Next, your integrating factor is p = e^[integral(1/x)dx] = e^(lnx) = x

Continue...

He didn't miss a term, your solution and his are identical, yours is just more detailed.
 
d_leet said:
He didn't miss a term, your solution and his are identical, yours is just more detailed.

Right :smile:
 
Thanks all, was really helpful.