Evaluating definite integral by substitution

dawn_pingpong
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Homework Statement


By using substitution u=\frac{1}{t}, or otherwise, show that

\int^∞_1 \frac{t^5}{(1+t^3)^3}dt=\int^1_0 \frac{u^2}{(1+u^3)^3}du

Homework Equations





The Attempt at a Solution


integral.png


Well, the reverse can also be done (making t to u). However, I don't know how to change the premise of the integral (from (∞,1) to (1,0). Thank you! I can integrate the integral after that.
 
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dawn_pingpong said:

Homework Statement


By using substitution u=\frac{1}{t}, or otherwise, show that

\int^∞_1 \frac{t^5}{(1+t^3)^3}dt=\int^1_0 \frac{u^2}{(1+u^3)^3}du

Homework Equations



The Attempt at a Solution


integral.png


Well, the reverse can also be done (making t to u). However, I don't know how to change the premise of the integral (from (∞,1) to (1,0). Thank you! I can integrate the integral after that.
\displaystyle \lim_{t\,\to\ \ \infty}\frac{1}{t}\ \ =\ \ \underline{\ \ ?\ \ }
 
0?

so the integral is just 0- \int\left[\frac{(1/t)^2}{t^2(1+(1/t)^3}\right]^1?(sorry don't really know how I'm supposed to write this...)

and at 0 the integral is 0. but it seems there is something wrong with the sign, because it is negative...
 
Last edited:
\displaystyle \int_a^b f(x)\,dx=- \int_b^a f(x)\,dx
 
oh right! thanks!
 
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