Evaluating Double Integrals of Odd and Even Functions on a Disk

ChiefKeeper92
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Homework Statement



Suppose f : ℝ→ℝ and g : ℝ →ℝ are continuous. Suppose that f is odd and g is even. Define h(x,y) : f(x)*g(y).
Let D be a disk centered at the origin in the plane. What is

∫∫h(x,y)dA?
D


The Attempt at a Solution


I know there's probably a trick to it. Is it 0 because h becomes odd over a disk that is symmetrical to the origin?
 
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Yes, that's basically it. Set it up as a dx*dy integral with limits if you want to show it explicitly.
 
ChiefKeeper92 said:
#Error

The problem posted was to evaluate the integral of h(x,y) over a disk D centered on the origin, where h(x,y)=f(x)g(y), f is an even function, g is odd.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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