Evaluation of Indefinite Integral

[futurept]

Homework Statement

Evaluate the following indefinite integral: (2t⁶-3)/t³ dt

The Attempt at a Solution

I know I need to substitute. Tried u= t³ and found du= 3t²dt. Tried to find where du would substitute in, but found nothing. Also tried u= 2t⁶-3. Found du=12t⁵dt and again cannot find where to sub in the du. Any suggestions on where I'm going wrong?

 

[Mark44]

Homework Statement

Evaluate the following indefinite integral: (2t⁶-3)/t³ dt

The Attempt at a Solution

I know I need to substitute. Tried u= t³ and found du= 3t²dt. Tried to find where du would substitute in, but found nothing. Also tried u= 2t⁶-3. Found du=12t⁵dt and again cannot find where to sub in the du. Any suggestions on where I'm going wrong?

You don't need to substitute. \frac{2t^6 - 3}{t^3} = 2t^3 -3t^{-3}. Now all you need to do is find antiderivatives for those two functions, using the power rule.

 

[futurept]

Hey thanks for the help!