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Evaluation of Indefinite Integral

  1. Dec 8, 2008 #1
    1. The problem statement, all variables and given/known data
    Evaluate the following indefinite integral: (2t6-3)/t3 dt



    3. The attempt at a solution
    I know I need to substitute. Tried u= t3 and found du= 3t2dt. Tried to find where du would substitute in, but found nothing. Also tried u= 2t6-3. Found du=12t5dt and again cannot find where to sub in the du. Any suggestions on where I'm going wrong?
     
    Last edited: Dec 8, 2008
  2. jcsd
  3. Dec 8, 2008 #2

    Mark44

    Staff: Mentor

    You don't need to substitute. [tex]\frac{2t^6 - 3}{t^3} = 2t^3 -3t^{-3}[/tex]. Now all you need to do is find antiderivatives for those two functions, using the power rule.
     
  4. Dec 8, 2008 #3
    Hey thanks for the help!!!
     
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