# Evaluation of Indefinite Integral

1. Dec 8, 2008

### futurept

1. The problem statement, all variables and given/known data
Evaluate the following indefinite integral: (2t6-3)/t3 dt

3. The attempt at a solution
I know I need to substitute. Tried u= t3 and found du= 3t2dt. Tried to find where du would substitute in, but found nothing. Also tried u= 2t6-3. Found du=12t5dt and again cannot find where to sub in the du. Any suggestions on where I'm going wrong?

Last edited: Dec 8, 2008
2. Dec 8, 2008

### Staff: Mentor

You don't need to substitute. $$\frac{2t^6 - 3}{t^3} = 2t^3 -3t^{-3}$$. Now all you need to do is find antiderivatives for those two functions, using the power rule.

3. Dec 8, 2008

### futurept

Hey thanks for the help!!!