1. The problem statement, all variables and given/known data Evaluate the following indefinite integral: (2t6-3)/t3 dt 3. The attempt at a solution I know I need to substitute. Tried u= t3 and found du= 3t2dt. Tried to find where du would substitute in, but found nothing. Also tried u= 2t6-3. Found du=12t5dt and again cannot find where to sub in the du. Any suggestions on where I'm going wrong?