Faiq said:
In explaining time dilation we usually say, if velocity of A is greater than velocity of B, then time is slower for A as compared to B. However, if vA> vB, using the equation for time dilation, tA>tB. So if 60 seconds passed for B, 100 seconds passed for A. How does that imply that time slowed down for A? Time, in above example, increased for A. So doesn't it means that time becomes faster for A?
You must use the Lorentz transformations and keep the concepts of proper time and time dilation straight. You have to be clear on what times you are referring to when you speak of t
A and t
B.
Proper time is the time measured by an observer on a clock that is at rest in the observer's frame of reference. This is necessarily a time between two events that are separated by time only, ie. not spatially separated, in the observer's frame.
The time intervals that observers in other inertial reference frames measure between two events are determined by the Lorentz transformations. The variable t represents time of an event in the "stationary" frame and t' represents time co-ordinate of an event measured in the frame moving at velocity v relative to the first.
Consider an observer in inertial reference frame A and an observer in inertial frame B whose origin is moving at velocity v in the direction of the x-axis relative to the origin of A. The proper time interval that observer in A measures on its own clock between event E1(0,0,0,t1)and event E2(0,0,0,t2) is t2-t1. An observer in B observes the same two events at E1(γ(x-vt1),y, z, γ(t1-vx/c
2) and E2(γ(x-vt2),y, z, γ(t2-vx/c
2) where x=y=z=0. So the time interval that B measures on its own clock between these events is ##\gamma (t2-t1)## which is greater than the time measured on A's clock. The result is that from B's perspective the time between events measured at the same location in A's frame of reference (A's clock at A's origin), which is moving at velocity -v relative to B, appear to be moving more slowly than B's.
If two events were to occur at the same location in B, A would observe the events to occur at
different locations in A and at a different time interval as measured by A on A's clocks. So it is perfectly symmetrical between the two inertial frames. It is just that what one observer sees as a pure interval of time the other sees as an interval of distance and a different interval of time.
Time dilation may be best demonstrated by the muon decay phenomenon. The proper lifetime of the muon is measured in the muon frame of reference. This lifetime can be determined in the laboratory from observing slow moving muons. Muons created in the upper atmosphere by cosmic ray bombardment create muons moving at relativistic speeds relative to the earth. We observe them reach the Earth surface. In order to do that they must survive for a time as measured on Earth that is significantly longer than their proper lifetimes. Based on our time measurements in the Earth frame of reference we say that the muon's clock appears to run slow. That is to say that the time between two events (muon creation to muon decay) is measured to be longer on Earth than it is in the frame of reference of the moving body. So, it appears to us that the fast moving muon's clock is running "slow". That is time dilation.
AM