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Homework Statement
An athlete executing a long jump leaves the ground at a 28° angle and travels 7.80 m. What was the takeoff speed?
Xo = 0
X = 7.80m
Ay = -9.8m/s^2
Homework Equations
V=Vo+at
X=Xo+VoT+(1/2)AT^2
V^2=V^2o+2A(X-Xo)
The Attempt at a Solution
I made a right triangle with a 28° angle in the proper corner and established that the starting X velocity was H(cos(28)) and starting Y velocity was H(sin(28)) where H is the hypotenuse (initial speed). I've no idea what to do or if I'm on the right track. I feel like the problem should be giving me more stuff, and at the same time I can kind of see how the logic would work but I've no idea how to apply it.
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