Expansion of Solids: Brass and Lead Rods at Different Temperatures

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The discussion focuses on calculating the separation of the free ends of a brass rod and a lead rod when heated from 0 to 100 degrees Celsius. The coefficients of linear expansion for lead and brass are provided, which are essential for the calculation. The formula for thermal expansion, delta L = alpha * L_initial * delta Temp, is applied to determine the change in length for both materials. The calculated separation of the free ends is determined to be 0.8 mm. This conclusion is reached by applying the thermal expansion formula correctly.
sudhamshu
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Q 1. A brass rod and a lead rod each 80 cm long at 0 degree celsius are clamped together at one end with their free end coinciding. The separation of the free ends of the rod if the system is placed in a steam bath at 100 degree celsius is ( coefficient of linear expansion of lead = 28*10^-6/degree celsius, coefficent of linear expansion of brass
= 18 * 10^-6/degree celsius) :
a. 0.2 mm
b. 0.8 mm
c. 1.4 mm
d 1.6 mm

Kindly Answer the above with the explanation
Sudhamshu
 
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Kindly show an effort, first. :smile:
 
Show us your work and where you got stuck. What's the basic equation describing thermal expansion?
 
is this the answer?

:smile:
0.8 because the formula is delta L=(alpha) (L initial)(delta Temp.)
 
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Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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