How Does a Proton Move in a Magnetic Field?

AI Thread Summary
A proton moving in a uniform magnetic field experiences a force described by F=qvB, leading to circular motion. The period of this motion is calculated as T= 2πm/qB. When entering the magnetic field from a non-magnetic region, the proton spends half of this period within the field. The discussion emphasizes understanding the relationship between the magnetic field strength and the proton's motion. The analysis provides a foundation for calculating the time spent in the magnetic field.
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Homework Statement

A proton enters a uniform magnetic field of strength B. Sketch it subsequent motion and derive an expression for the time, t, spent in the magnetic field.

Homework Equations



F=qvB=mv^{2}\div r

The Attempt at a Solution



I calculated the period of the particle in the field as:

T= 2 \pi m\div qB

I don't know if this is what they want or if there's a way to calculate the total time.
 
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A delayed reply, but this one looks like just what you had asked.

http://regentsprep.org/Regents/physics/phys03/cdeflecte/default.htm
 
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A charged particle will spend 1/2 period in a magnetic field (assuming it's constant) when it enters at the boundary from a region without the magnetic field.
 

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