Can Negative Current Occur in Simple Circuit Designs?

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Negative current in simple circuit designs, such as the one discussed, is generally considered impossible unless a different reference node is chosen. The voltage at a specific node must remain higher than ground, making it unlikely for current I3 to be negative. While current direction can be altered by the orientation of arrows, the fundamental voltage relationships dictate that I3 cannot reverse direction in the given circuit. However, if element 4 is a voltage source or current source, it could theoretically allow for negative current. Ultimately, the discussion emphasizes that the sign of current is a matter of perspective and adherence to Kirchhoff's principles.
sherrellbc
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I've seen this simple circuit design many times when the text is illustrating different points. Sometimes, again for illustrative purposes, the text may say that I3 is negative. When would this ever happen? If I3 were negative, the node between components 3 & 4 would have to be lower than ground, and, further, the red extraordinary node would have to be lower yet. It seems intuitive to me to conclude that the voltage at the node in red will never be at a lower potential than ground in this design. If I3 is negative, it would seem obvious to me that I2 must also be negative (with polarity defined as is it) - but when could this be the case?

Perhaps I3 could be negative if different node is selected as the reference, but as it stands I cannot see a way that this claim would ever be true.

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IN my mind, I3 can never be negative in this circuit.

Lets say the battery is 20 volts and 10 volts drop across that first resistor. YOu are then left with 10 volts at the red node. No matter how you slice it, current is going to travel in the shown direction just because that voltage will always be higher than the negative side of the battery.

You could say that I3 is negative if the arrow pointed the other way, but that's it.
 
psparky said:
IN my mind, I3 can never be negative in this circuit.

Lets say the battery is 20 volts and 10 volts drop across that first resistor. YOu are then left with 10 volts at the red node. No matter how you slice it, current is going to travel in the shown direction just because that voltage will always be higher than the negative side of the battery.

You could say that I3 is negative if the arrow pointed the other way, but that's it.

Eactly. Although, I did not intend to post this picture implying the elements are resistors. I had forgotten that european resistor symbols are rectangles.
 
sherrellbc said:
Eactly. Although, I did not intend to post this picture implying the elements are resistors. I had forgotten that european resistor symbols are rectangles.

Doesnt matter, I just pictured them as loads.

You might be able to stop the current with a capacitor or diode, but the current can't reverse direction in I3.
 
Unless they're using electron flow for current.
 
If you are doing a node analysis for the red dot - it is ( may be ) simpler to have all of the currents flowing into - or out of the red dot - EG I1+I2+I3 = 0A ... so you may draw the arrows how you like.

My point being - that the issue of positive or negative is a matter of perspective.
 
sherrellbc said:
... I did not intend to post this picture implying the elements are resistors...
Is there any restriction on what they could be? If element 4 is a voltage source, a sufficiently charged capacitor, or a current source, it is possible for i3 to be negative.
 
My guess would be it is simply to demonstrate that, even if you initially assume I3 in wrong direction, Kirchoff's principles will cause the arithmetic solution give you the correct answer - a negative number for I3.

My high school electronics teacher pounded this point into us boys so we'd develop rigor (and faith) in our math .

old jim
 
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