Exponential equation - how to use ln?

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    Exponential Ln
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Homework Help Overview

The problem involves solving an exponential equation of the form 64000e^{-1600t}+4000e^{-400t}=50000e^{-1000t} for the variable t. Participants are exploring the manipulation of the equation and the use of logarithms in their attempts to isolate t.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss factorization of the equation and express uncertainty about applying the natural logarithm to multiple terms. One participant suggests a substitution to simplify the equation into a quadratic form.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and insights. Some guidance has been provided regarding the transformation of the equation into a simpler form, but there is no explicit consensus on the best approach to take.

Contextual Notes

Participants note that the numbers in the equation seem convenient for solving, raising questions about the generalizability of their methods to less straightforward cases. There is an acknowledgment of the typical nature of problems encountered at the high school level.

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Homework Statement


Problem: find t in the following equation

Homework Equations



64000e^{-1600t}+4000e^{-400t}=50000e^{-1000t}

The Attempt at a Solution



I know the answer: t=6.17\cdot\;10^{-4}s. But I'm struggling with how to get there. This is my attempt:

Factorizing down to:

1000(64e^{-1600t}+4e^{-400t}-50e^{-1000t})=0

and further on:

1000e^{-400t}(64e^{-1200t}+4-50e^{-600t})=0

I realize only what's in the paranthesis is needed, since the 1000e...is never zero:

(64e^{-1200t}+4-50e^{-600t})=0

I want to ln both sides, but I'm not quite sure how to do that, since there are three parts...
 
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dragonblood said:

Homework Statement


Problem: find t in the following equation


Homework Equations



64000e^{-1600t}+4000e^{-400t}=50000e^{-1000t}

The Attempt at a Solution



I know the answer: t=6.17\cdot\;10^{-4}s. But I'm struggling with how to get there. This is my attempt:

Factorizing down to:

1000(64e^{-1600t}+4e^{-400t}-50e^{-1000t})=0

and further on:

1000e^{-400t}(64e^{-1200t}+4-50e^{-600t})=0

I realize only what's in the paranthesis is needed, since the 1000e...is never zero:

(64e^{-1200t}+4-50e^{-600t})=0

I want to ln both sides, but I'm not quite sure how to do that, since there are three parts...

Big hint of the day: If you let x = e-600t. Then what does your last equation become?
 
Aha! So i get a simple second degree equation: 64x^{2}-50x+4=0

Thanks :)

But I'm thinking now that these numbers were 'convenient'...are there other ways to solve this if the numbers don't play along this nicely?
 
dragonblood said:
Aha! So i get a simple second degree equation: 64x^{2}-50x+4=0

Thanks :)

But I'm thinking now that these numbers were 'convenient'...are there other ways to solve this if the numbers don't play along this nicely?

Well, I can assure that, you'll rarely meet an inconvenient problem in high school, especially when you are just getting familiar with exponential equations like this.

After some substitution, an exponential equation in general, will become a quadratic equation, or cubic equation, or even a quartic equation (but in special cases, like: ax4 + bx2 + x = 0, which then can easily be taken down to a quadratic equation by letting t = x2).

So, don't worry. :)
 

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