Expression of AM Cosine Wave using Phasors

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An AM cosine wave can be expressed using phasors by rewriting the equation x(t)=12+7*sin(pi*t-(1/3)*pi)*cos(13*pi*t). To achieve the desired form A1cos(w1*t+phi1) + A2cos(w2*t+phi2) + A3cos(w3*t+phi3), one can utilize the relationships between sine and cosine functions and their exponential forms. By substituting the sine and cosine components with their respective exponential expressions, the terms can be multiplied and grouped by angular frequency. This method allows for the identification of the coefficients A1, A2, and A3 along with their corresponding phases. The approach provides a systematic way to analyze and express the AM cosine wave in the required format.
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An AM cosine wave is represented by x(t)=12+7*sin(pi*t-(1/3)*pi)]*cos(13*pi*t). Use phasors to show that x(t) can be expressed in form of:

A1cos(w1*t+phi1) + A2cos(w2*t+phi2)+A3cos(w3*t+phi3) where w1<w2<w3.

I am really stuck with this. don't know where to start. can someone please help me out?
 
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yoyo said:
An AM cosine wave is represented by x(t)=12+7*sin(pi*t-(1/3)*pi)]*cos(13*pi*t). Use phasors to show that x(t) can be expressed in form of:

A1cos(w1*t+phi1) + A2cos(w2*t+phi2)+A3cos(w3*t+phi3) where w1<w2<w3.

I am really stuck with this. don't know where to start. can someone please help me out?

Use that

cos(\omega t +\phi)= \frac{e^{i(\omega t + \phi)}+e^{-i(\omega t + \phi)}}{2}

and

sin(\omega t +\phi)= \frac{e^{i(\omega t + \phi)}-e^{-i(\omega t + \phi)}}{2i}

Replace the sin and cos functions in x(t) with the exponential expressions, do all the multiplications, collect the terms with the same angular frequency and see what you get.

ehild
 
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