- #1

- 5

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Any suggestions im sure I need to set the limit to less than or equal to and greater than or equal to the max but i dont quite know how

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- Thread starter Hunterelite7
- Start date

- #1

- 5

- 0

Any suggestions im sure I need to set the limit to less than or equal to and greater than or equal to the max but i dont quite know how

- #2

- 341

- 0

keep it simple and start with taking two elements a,b and take the power of 20th...

- #3

- 5

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im sorry im having a hard time folowing yor terminology is there any way to rephrase

- #4

- 341

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[tex]

\left(\int_0^1{|f(t)|^p dt}\right)^{1/p} \leq \left(\int_0^1{\underbrace{(\max{|f(t)|})^p}_{const} dt}\right)^{1/p}=\max|f(t)|\int_0^1{dt}=\max|f(t)|

[/tex]

This proof lacks only one limiting argument, can you find it?

- #5

- 5

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ok so how do I show the opposite or that the function is greater than or equal to the max

- #6

HallsofIvy

Science Advisor

Homework Helper

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What function and the max of what?

- #7

- 5

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the function is just vague f(t) and the max is the maximum of |f(t)| between [0,1]

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