1. Jul 24, 2013

### assaftolko

1. The problem statement, all variables and given/known data
A rectangular loop moves with constant speed v towards an area in space with constant magnetic field B (As shown in the attachment). The loop enters this area and leaves it from the other side. Also given: d>c. Assume that t=0 when the left edge of the loop is just on the right edge of the magnetic field area. Assume positive induced emf when it generates induced current clock-wise in the loop.

2. Relevant equations
Well I'm asked to calculate 4 things in this problem, I'm interested in one of them:
Now, instead of moving with constant speed v, the loop is accelerated with constant acceleration a. The loop starts at rest when its left edge is just on the right edge of the magnetic field area. When will the induced current in the loop will be maximal?

3. The attempt at a solution
According to the solution the induced current will be maximal in two moments (and equal in both of them): When the loop is just about to completly enter the area of magnetic field and when the loop is just about to completly leave this area. Two questions:
1. As the loop leaves the area - its area that's subjected to the magnetic field decreases with time - so wouldn't we expect that the induced current will be maximal just as it starts to leave the area?
2. Why would the maximal induced current be the same in these 2 cases? Time is increasing as the problem starts - and since the induced emf is a function of t in the case of acceleration - how does it make sense that the induced emf will be equal like the solution states?

#### Attached Files:

• ###### Clipboard01.jpg
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2. Jul 24, 2013

### rude man

Rather than approach this problem via d(phi)dt, use the BLv formula on both sides of the coil perpendicular to the velocity vector. Realize that the emf of the back (right) side of the coil will counter the emf developed on the front (left) side.