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- Thread starter Kairos
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- #2

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The twin paradox is just this same phenomenon but in a Minkowski space not a Euclidean one. In Minkowski geometry the straight line between two (timelike separated) points is the longest distance (or

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Ok the second is unchanged but on arrival, there will be less counted on the traveler's quartz watch. Thank you I will meditate on this result!(1); The traveling twin has experienced fewer seconds

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Rather than meditating I recommend drawing Minkowski diagrams, marking the seconds (or years or whatever) along each path, in the stay-at-home frame and the traveller's inbound and outbound frames. In fact, if you look up posts by former poster @ghwellsjr you will probably find exactly that fairly quickly.Ok the second is unchanged but on arrival, there will be less counted on the traveler's quartz watch. Thank you I will meditate on this result!

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You're welcome.Ok the second is unchanged but on arrival, there will be less counted on the traveler's quartz watch. Thank you I will meditate on this result!

From Wikipedia-Second

The twin brothers share this definition of time. The traveling brother has his Ce133 clock which shows his second. The Earth brother has his Ce133 clock which shows his second.The second is defined as being equal to the time duration of 9 192 631 770 periods of the radiation corresponding to the transition between the two hyperfine levels of the fundamental unperturbed ground-state of the caesium-133 atom.[1][2]

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Rather than meditating I recommend drawing Minkowski diagrams

These diagrams are graduated using the letter "t" but it was not clear to me whether dt > dt' corresponds to a dilation of the second or an increase in the number of seconds.

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I'm struggling to understand what you mean. The twin paradox is exactly what I said it is in #2 - two paths which have different "lengths" and form a triangle. In Euclidean space I would not describe the difference in path lengths as due to either "a dilation of the meter" or "an increase in the number of meters". Nor would I use your terminology to describe the exact same thing in Minkowski spacetime. It's just two paths of different lengths.These diagrams are graduated using the letter "t" but it was not clear to me whether dt > dt' corresponds to a dilation of the second or an increase in the number of seconds.

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The second is defined in a specific frame of reference, namely the rest frame of the Cs-133 atoms and the frequency of the hyperfine transition as measured in this reference frame.These diagrams are graduated using the letter "t" but it was not clear to me whether dt > dt' corresponds to a dilation of the second or an increase in the number of seconds.

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Shouldn't that be “longer” instead of “shorter”?(2) the number of seconds is the same for both brothers but the traveler's seconds are shorter?

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Nugatory

Mentor

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Wonderful stuff, this natural language......Shouldn't that be “longer” instead of “shorter”?

It depends on whether a "shorter" second is one during which we age less, or one that it takes more of to fill the gap between the separation and arrival times. Like one of those reversing perspective line drawings of a cube, I can read it either way.

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sorry for the delay. No because n longer time units would have given a longer total duration whereas the traveller is younger on arrival.. but there is no need to argue about this point given the universality of the secondShouldn't that be “longer” instead of “shorter”?

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no, the time dilation of the SR is reciprocal and not sufficient to explain the age difference in the twins' experiment

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OK and I suppose that a unit of time defined using the cesium 133 or any other atomic transition, is also the same as measured in the reference frame of other contexts (acceleration, gravity) ?The second is defined in a specific frame of reference, namely the rest frame of the Cs-133 atoms and the frequency of the hyperfine transition as measured in this reference frame.

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Time dilation is rarely sufficient to explain anything. It's quite common when learning SR to learn time dilation first and then, armed with that alone, try to explain certain phenomena. Time dilation is not enough: in SR you have time dilation, length contraction and the relativity of simultaneity. These three are encapsulated by the Lorentz Transformation. - and generally you need all three to explain anything.no, the time dilation of the SR is reciprocal and not sufficient to explain the age difference in the twins' experiment

The relativity of simultaneity is so important that, personally, I would teach that first so that hopefully nobody tries to do anything using only time dilation.

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I am about 6 feet tall or about 2 m tall. So according to you a m is shorter than a foot?sorry for the delay. No because n longer time units would have given a longer total duration whereas the traveller is younger on arrival.. but there is no need to argue about this point given the universality of the second

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according to me, 6 m is taller than 6 feet because m is a longer unit..

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So you agree that a m is longer than a foot.according to me, 6 m is taller than 6 feet because m is a longer unit..

Then if two people measure my height, one in m and one in ft, then the person measuring my height in m will get a smaller number than the person measuring my height in ft. So the smaller number corresponds to the larger unit.

The traveller records a smaller number so it must be a larger unit, yes? If not, I don’t know at all what you are talking about in your OP at all.the number of seconds is the same for both brothers but the traveler's seconds are shorter?

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In other reference frames, where the emitting atom is moving, the spectral lines are Doppler shifted. If gravity is considered, you have to use General Relativity to calculate the corresponding shift of the frequency of the emitted em. waves, and this is closely related to relativistic time dilatation. When calculated with GR, it contains both the Doppler and the gravitational shifts of the frequency.OK and I suppose that a unit of time defined using the cesium 133 or any other atomic transition, is also the same as measured in the reference frame of other contexts (acceleration, gravity) ?

The twin paradox is something slightly different. Here you compare the proper time between the departure of the twins from each other and compare their proper times when meeting again. These proper times of each twin, i.e., there aging between departure and meeting again, are what clocks traveling with each of the twins measure, and it's a scalar quantity, i.e., independent of any space-time coordinates used to describe the motion of the twins and calculating their proper times. Such and only such quantities are of true and unambigous physical significance.

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So you agree that a m is longer than a foot.

Then if two people measure my height, one in m and one in ft, then the person measuring my height in m will get a smaller number than the person measuring my height in ft. So the smaller number corresponds to the larger unit.

There is a misunderstanding, please read my initial question. The duration of the trip is shorter for the traveler than for the sedentary. I was just considering two possibilities for this: (1) they did not count the same number of seconds during the travel interval or (2) they would have counted the same number of seconds without realizing that a second would not have the same value. But the question, certainly stupid, is definitely answered: the first hypothesis is right, the second hypothesis wrong. Thanks

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OK thanks. My question was in the same reference frame. Whether cesium 133 is far from any mass or in a very intense gravitational field, the second defined using this cesium in its reference frame will always be exactly the same, is it correct?In other reference frames, where the emitting atom is moving, the spectral lines are Doppler shifted. If gravity is considered, you have to use General Relativity to calculate the corresponding shift of the frequency of the emitted em. waves, and this is closely related to relativistic time dilatation. When calculated with GR, it contains both the Doppler and the gravitational shifts of the frequency.

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The simple answer is yes.OK thanks. My question was in the same reference frame. Whether cesium 133 is far from any mass or in a very intense gravitational field, the second defined using this cesium in its reference frame will always be exactly the same, is it correct?

A fuller answer is that the theory of GR predicts that proper time (as measured by a perfect clock) is a measure of spacetime distance. You can take cesium 133 as a definitive measure of time locally.

Take two laboratories starting out together then taking different paths through spacetime. In each laboratory local experiments have the expected outcomes: the half life of radioactive elements; the behaviour of a cesium clock and anything else. If the two laboratories come back together, then their cesium clocks may show different elapsed time. Everything that happened in each laboratory obeyed the same laws of physics in the same way. But, the paths they took through spacetime were of different lengths (different total proper time) - literally, therefore, more proper time passed for one lab than the other.

GR is very much about the nature of time and not the specific workings of clocks.

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$$\tau_j = \frac{1}{c} \int_{\lambda_{j1}}^{\lambda_{j2}} \mathrm{d} \lambda \sqrt{g_{\mu \nu} \dot{x}^{\mu} \dot{x}^{\nu}}.$$

These two scalar quantities give the proper time passed and thus the aging of each of the twins. Case closed.

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Of course within GR the frequency used to define the 2nd has to be measured locally in a local inertial rest frame of the Cs atom to define the second.OK thanks. My question was in the same reference frame. Whether cesium 133 is far from any mass or in a very intense gravitational field, the second defined using this cesium in its reference frame will always be exactly the same, is it correct?

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