The discussion focuses on calculating the final temperature of tea after pouring it into a glass cup. The initial conditions are 0.22 liters of tea at 95 degrees Celsius and a 150-gram glass cup at 25 degrees Celsius. A user attempted to solve the equation 0.21(95-T) = 150(25+T) but realized the need to correctly use 0.22 instead of 0.21. The correct approach involves setting up the heat transfer equation properly to find the final temperature. Accurate calculations are essential for determining the final temperature in this scenario.
#1
shayur goorah
4
0
If 0.22L of tea at 95 degrees C, is poured into a 150g glass cup initially at 25 degrees C, what will the final temperature be, assuming no heat is lost to the surroundings?
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19.
For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Let's declare that for the cylinder,
mass = M = 10 kg
Radius = R = 4 m
For the wall and the floor,
Friction coeff = ##\mu## = 0.5
For the hanging mass,
mass = m = 11 kg
First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on.
Force on the hanging mass
$$mg - T = ma$$
Force(Cylinder) on y
$$N_f + f_w - Mg = 0$$
Force(Cylinder) on x
$$T + f_f - N_w = Ma$$
There's also...
This problem is two parts. The first is to determine what effects are being provided by each of the elements - 1) the window panes; 2) the asphalt surface. My answer to that is
The second part of the problem is exactly why you get this affect.
And one more spoiler: