Find 3tan^2A+4tan^2B for A,B Real Numbers

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To find the value of 3tan^2A + 4tan^2B for real numbers A and B, the equation 2(sinA + cosB)sinB = 3 - cosB is given. The discussion involves expanding the expression using trigonometric identities, leading to 3sin^2A*cos^2B + 4sin^2B*cos^2A over cos^2A*cos^2B. There is confusion regarding the notation of variables, specifically whether "A" and "B" should be treated as distinct from "a" and "b." The thread highlights the need for clarity in variable representation to proceed with the solution. The conversation emphasizes the importance of understanding trigonometric relationships in solving the problem.
romsofia
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1. Homework Statement A and B are real numbers satisfying 2(sinA+cosB)sinB=3-cosB. Find 3tan^2A+4tan^2B
2. Homework Equations Trig Identities
3. The Attempt at a Solution well, i expanded 3tan^2A+4tan^2B= 3sin^2A*cos^2B+4sin^2B*cos^2A all over cos^2A*cos^2B after that I am stuck :x
 
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Are we to assume that "A" is the same as "a" and that "B" is the same as "b"?
 
HallsofIvy said:
Are we to assume that "A" is the same as "a" and that "B" is the same as "b"?

yes, let me edit that :x
 
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