Find an expression for the electrostatic energy of this charge distribution.

AI Thread Summary
The discussion focuses on finding an expression for the electrostatic energy of a charge distribution involving charges 'q' and 'q/2'. Participants clarify the correct distance for the diagonals of a square, confirming it should be √2a, not √a. The conversation emphasizes making appropriate substitutions for the charges and simplifying the expression for energy. Simplification involves factoring out q² and combining terms over a common denominator. The overall goal is to derive a clear formula for the electrostatic energy based on these calculations.
warnexus
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Homework Statement


electro.jpg




Homework Equations


work = kqqq/(distance)


The Attempt at a Solution


http://i33.photobucket.com/albums/d86/warnexus/electrodiag.jpg

energyexpression.jpg
 
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Check the distance you've used for the diagonals. Substitute 'q' and 'q/2' for the appropriate charges and simplify.
 
the distance I used for the diagonals is sqrt of a. I do not understand I do not have q/2.
 
warnexus said:
the distance I used for the diagonals is sqrt of a. I do not understand I do not have q/2.

Is the length of a diagonal of a square of side length a equal to √a ?

You have two sizes of charge: One is 'q', the other is 'q/2'. Make the appropriate symbolic substitutions.
 
gneill said:
Is the length of a diagonal of a square of side length a equal to √a ?

You have two sizes of charge: One is 'q', the other is 'q/2'. Make the appropriate symbolic substitutions.

oops the diagonal is suppose to be sqrt 2a^2.

heres the substitutions:

k(qq/a + qq/sqrt(2a^2) + qq/a -1/2qq/a -1/2qq/a -1/2qq/sqrt(2a^2))
 
Last edited:
Okay, but you can simplify further. For example, you can pull out the q2 from each term.
 
gneill said:
Okay, but you can simplify further. For example, you can pull out the q2 from each term.

heres the simplification

kqq(1/a + 1/sqrt(2a^2) + 1/a - (1/a) - (1/2)/sqrt (2a^2)
 
You can collect the terms, putting them over a common denominator...
 
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