Find Area Enclosed by Thermodynamic Cycle

jackscholar
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Homework Statement


The question is pretty much explained in the picture.
The area ABCD is enclosed, i need to find that area. The equation for AB is P=0.8+8.6e^(-0.3V) and the equation for CD is P=1.2+9.6e^-(0.1V)
What I did was find the area enclosed by the rectangular shape (C-B)*9. From there I subtracted the integral of the equation AB with the upper and lower limits 2.076 and 0.159 respectively. I then surmised that if I subtracted the integral of AB from (25 (upper) to 2.076 (lower)) from CD then it would give me the rest of the Area. I ended up getting 67.7 doing this. Is this correct?
 

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jackscholar said:

Homework Statement


The question is pretty much explained in the picture.
The area ABCD is enclosed, i need to find that area. The equation for AB is P=0.8+8.6e^(-0.3V) and the equation for CD is P=1.2+9.6e^-(0.1V)
What I did was find the area enclosed by the rectangular shape (C-B)*9. From there I subtracted the integral of the equation AB with the upper and lower limits 2.076 and 0.159 respectively. I then surmised that if I subtracted the integral of AB from (25 (upper) to 2.076 (lower)) from CD then it would give me the rest of the Area. I ended up getting 67.7 doing this. Is this correct?

That answer is OK, rounded to 3 significant figures.
 
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