Find Equilibrium Readings of Scale: Beaker & Oil + Iron Block

AI Thread Summary
To find the equilibrium readings of the scales, first calculate the buoyant force acting on the submerged iron block, which is equal to the weight of the oil displaced. The buoyant force can be determined using the formula: buoyant force = density of oil × volume of iron block × g. The reading on the bottom scale will be the combined weight of the beaker and oil plus the weight of the iron block minus the buoyant force. The upper scale will read the weight of the iron block, which is affected by the buoyant force as it exerts an upward reaction on the liquid. Understanding these forces is key to solving the problem accurately.
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A 1-kg beaker containing 2 kg of oil(density = 916 kg/m^3) rests on a scale. A 2kg block of iron is suspended from a spring scale and completely submerged in the oil. Find the equilibruim readings of both scales.

For the bottom scale, I can find the weight, 29.4 N of the beaker and oil, but I'm not sure how to calculate how much weight the iron block contributes. I know buoyancy force = p*V*g but how would affect the weight on the scale?
 
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HINT: If the liquid pushes up (buoyant force) on the iron what is the reaction force acting on the liquid?
 
any more help? I am working with my daughter trying to solve this.
 
So one more cry for help. How do I calculate the reading on the lower and upper scale given what I know in the problem stated above?

Thanks!
 
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