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Find field intensity at center of toroid?

  1. Feb 22, 2015 #1
    1. The problem statement, all variables and given/known data
    I really think my answer is correct - could someone verify this or let me know where I went wrong? This is problem submitted online, the "correct" answer looks like my teacher accidentally hit the button 3 twice.
    PROBLEM:
    The toriod in example 5-1 from the textbook has an inner diameter of 3.1 cm and an outer diameter of 4 cm. 8 amps are flowing through 41 turns on the toroid.

    What is the field intensity very close to the inside diameter (A/m)?

    See attachment for figure.

    2. Relevant equations
    Rm = 0.5*(Di+Do)/2
    H = Ni/L
    L = 2*PI*Rm

    Simply find H.

    3. The attempt at a solution
    I plugged in the numbers many times and keep getting 367.62. My teacher got 3367.92. Looks like the 3 was clicked twice? Any help appreciated.
     

    Attached Files:

  2. jcsd
  3. Feb 22, 2015 #2

    TSny

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    I'm getting the same answer as your teacher. Note that you are asked to find the field "very close to the inside diameter".
     
  4. Feb 22, 2015 #3
    Okay. Here are my steps
    1) Find Rm = (0.01775)/4= 0.01775
    2) Find H = Ni*I/(2*PI*Rm) = 42*8/(2IPI*.01775 = 3012.8

    I forgot to put the I in my first answer.

    I don't see the importance of the "very close to the inside diameter" part and how that effects the equation.
     
  5. Feb 22, 2015 #4

    TSny

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    You are using the mean value of R: Rm. But you need to use the value of R that corresponds to being close to the inner diameter.

    Did you derive the formula for H in class using Ampere's law, or were you just given the formula without a derivation?
     
  6. Feb 22, 2015 #5
    We were not given it. Maybe they just assume I could derive it? Not sure. But I think I see what you are saying. So rather than going to the Rm, I should just use Ri -->
    Ri = .031/2
    Didn't derive it but that gives the right answer. Thanks.
     
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