Find functions with given domain and range

xsw001
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1) Find a continuous function f: (0,1)->R with f[(0,1)]=R
I couldn't think of any function except tangent, but its domain is NOT (0,1) though? Any suggestions?

2) Find a continuous function f: (0,1)->R with f[(0,1)]=[0,1]
I couldn't think of any function that I know. Any suggestions?

3) Find a continuous function f: R->R this is strictly increasing and f(R)=(-1,1)
The graph is somewhat look like f(x)=x^(1/3), but not exactly though since the domain doesn't fall into (-1,1). Any suggestions?
 
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xsw001 said:
1) Find a continuous function f: (0,1)->R with f[(0,1)]=R
I couldn't think of any function except tangent, but its domain is NOT (0,1) though? Any suggestions?

Not a bad idea. Modify it to f(x)=tan(ax+b) and figure out what a and b should be.

2) Find a continuous function f: (0,1)->R with f[(0,1)]=[0,1]
I couldn't think of any function that I know. Any suggestions?

You're being asked to find a function whose range is [0,1]. Surely you can immediately come up with 2 examples.

3) Find a continuous function f: R->R this is strictly increasing and f(R)=(-1,1)
The graph is somewhat look like f(x)=x^(1/3), but not exactly though since the domain doesn't fall into (-1,1). Any suggestions?

I'm thinking arctangent here.
 
Okay, I got the first and third one, but can you provide me some oscillated function for the 2nd one though? I know it has to do with 1/[x(x-1)], but the graph is not exactly in between [0,1] though.
 
Why not use sine or cosine?
 
Oh, yeah, thanks!
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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