Find how much a wire stretched at the bottom of swing of pendulum

AI Thread Summary
To determine how much the steel wire stretches at the bottom of the swing of a pendulum, the discussion emphasizes using energy conservation to find the velocity at the lowest point. The key equations involved are stress (F/A), strain (ΔL/L), and Young's Modulus (Y). The calculated tension at rest is 3924N, leading to an initial stretch of 0.03 cm. However, the challenge lies in accounting for the additional acceleration when the pendulum is in motion. The conversation highlights the need to incorporate both static and dynamic forces to accurately assess the wire's stretch.
rezihk
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1. A building is to be demolished by a 400kg shell ball swinging on the end of a 30.0 m steel wire of diameter 5.00 cm hanging from a tall crane. As the ball is swung though an arc from side to side, the wire makes an angle of 50° with the vertical at the top of the swing. find the amount by which the wire is stretched at the bottom of the swing



2. stress=F/A, strain=ΔL/L, F=ma, Y= Young's Modulus



3. ΔL=F/A*L/Y

 
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I suppose you have the problem at finding the force. User Energy conservation to find the velocity at the lowermost point. Then use the equation T-mg = mv^2/(L+ΔL)
 
vivek, let the guy show some work at least. that's the forum policy. the person has not shown ANY work.
 
i figured out all these values and plugged them into the eqn i have:

A=1.96E-3 m^2 wire
Y=20E10
L=30m
Tension if it were at rest and bottom: T=mg=3924N
and got dL=0.03cm
but I'm assuming at it stretches the same if it were at rest or accelerating when at the bottom
how do i take acceleration into account?
 
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