Find if a function is the Laplace transform of a periodic function

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Homework Help Overview

The discussion revolves around whether the function \[F(s) = \frac{1}{{s(1 - {e^{ - s}})}\] can be the Laplace transform of a periodic function. Participants are exploring the implications of this question and the characteristics of periodic functions in relation to Laplace transforms.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the properties of the Laplace transform and its relationship to periodic functions. There is an exploration of the inverse Laplace transform and the nature of the stairs function as a potential candidate for periodicity.

Discussion Status

The conversation is ongoing, with some participants questioning the periodicity of the stairs function and the requirements for a function to be considered periodic in the context of Laplace transforms. There is a recognition that the inverse Laplace transform of certain functions may not yield periodic results, prompting further inquiry into the theoretical aspects of the problem.

Contextual Notes

Participants are grappling with the theoretical nature of the question, indicating that the exercise may require more than just finding a periodic function, but rather understanding the underlying principles that determine periodicity in relation to Laplace transforms.

libelec
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Homework Statement



Could [tex]\[F(s) = \frac{1}{{s(1 - {e^{ - s}})}}\][/tex] be the Laplace transform of some periodic function? Why? If so, find that periodic function

The Attempt at a Solution



If it was the Laplace transform of some periodic function, the the Laplace transform of the first wave should be 1/s, and the period T should be 1. The function whose Laplace transform is 1/s is H(t). Then the periodic function should be the stairs function, [tex]\[f(t) = \left\{ \begin{array}{l}<br /> n,x \in [nT,(n + 1)T] \\ <br /> n + 1,x \in [(n + 1)T,(n + 2)T] \\ <br /> \end{array} \right.,n \in N + \left\{ 0 \right\}\][/tex]

Now, the stairs function is of exponential order, since it's smaller or equal than the function t+1 for all t, and that is an exponential order function. Then it has a Laplace transform.

So far, so good. If the stairs function transforms to F(s) there, then F(s) is the Laplace transform of some periodic function.

But I don't think that's what the exercise asks me to do, since a latter question asks me to find the periodic function. I think there's something I have to prove through F(s) that allows me to say that it is the Laplace transform of a periodic function.

But I don't know what is that.

Any ideas?
 
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I'm thinking the answer is no and you should be thinking about the "why" rather than trying to find a periodic function. Your stairs function certainly isn't periodic...
 
Allright, it's true.

But then why couldn't it be periodic? Is it because the inverse Laplace transform of 1/s is H(t), and that isn't a periodic function? What does F(s) has to have to check if it belongs to a periodic function or not?
 
libelec said:
Allright, it's true.

But then why couldn't it be periodic? Is it because the inverse Laplace transform of 1/s is H(t), and that isn't a periodic function? What does F(s) has to have to check if it belongs to a periodic function or not?

Well, I didn't check your steps, but I assume you have the correct inverse with your staircase function. It isn't periodic and the FT is a 1-1 transform so doesn't that settle it?
 
Yes, but I thought there was another argument to say that. I mean, since the question seems to be theorical.
 
Anybody?
 

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