Find Induced Voltage in Rotating Conductor in Radial Field

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The discussion centers on calculating the induced voltage in a rotating conductor within a radial magnetic field. A conductor 1 cm long rotates at 1200 revolutions per minute in a magnetic field defined by B = 0.5 a_{r}. The participants clarify that induced voltage, or electromotive force (emf), can occur even without a closed circuit, as the magnetic field exerts a force on electrons, prompting movement. The relationship between induced voltage and motion is explained through the equation V = vBL, where v is the velocity and B is the magnetic field strength. The complexity of the situation arises from the varying velocity along the length of the conductor.
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Homework Statement


A conductor 1 cm in length is parallel to z axis and rotates in a radius of 25 cm at 1200 rev/min , find induced voltage if radial field is given by B = 0.5 a_{r}

Homework Equations





The Attempt at a Solution


i am confused. If there is no closed path then how the voltage can be induced
 
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Voltage (actually emf) is induced in any material of any kind - even a vacuum! - over a length dL:

dV = (B x dL) * v
where B is magnetic field and v is the velocity of the element of length dL. Vectors in bold.

The direction of dL is in the direction of conventional current under the assumption of a closed circuit. But there need not be a closed circuit.
 
hi erece! :smile:
erece said:
If there is no closed path then how the voltage can be induced

the magnetic field causes a force, so that the electrons to "want" to move along the wire

whether they can is irrelevant … there is a gravitational potential difference between the table and the floor even if the things on the table cannot fall to the floor! :biggrin:

voltage = potential energy difference per charge = work done per charge (V = W/q)

work done = force "dot" displacement

for example, if a rod of length L moves at speed v perpendicularly to a uniform magnetic field B, then the force on a charge q inside the rod is qvB along the rod,

so the work done moving it a distance L along the rod is ∫ qvB dx = qvBL,

and the work done per charge is vBL,

ie V = vBL​

ok, that's for linear motion, where v is constant (along the rod) …

in your case, v changes along the rod, so the work done integral (∫ qvB dx) will be more complicated :smile:
 
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