Find Kmax with given numerical quantities

AI Thread Summary
The discussion revolves around calculating K(max) using the formula K(max) = (6.63x10^-34 J s)(7.09x10^14 s) - 2.17x10^-19 J. Participants point out that the units in the equation are inconsistent, as combining J s² with J is not valid. It is suggested that the first term should be corrected to (6.63x10^-34 J s^-1) to reflect Planck's constant properly. The confusion stems from a likely typo regarding the units involved. Clarifying these units is essential for solving the equation correctly.
xpaulinabearx
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Homework Statement



K(max) = (6.63x10^-34 J s)(7.09x10^14s) - 2.17x10^-19J
solve for kmax

Homework Equations



none?

The Attempt at a Solution


K = (6.63x10^-34 J s)(7.09x10^14 s) - (2.17x10^-19 J)
K = (6.63)(7.09)(10^-34)(10^14) J s^2 - (2.17x10^-19 J)
K = (47.0067)(10^-24) J s^2 - (2.17x10^-19 J)
K = (4.70067x10^-23) J s^2 - (2.17x10^-19 J)
K = J [ (4.70067x10^-23) s^2 - (2.17x10^-19) ]
K = J (10^-19) [ (4.70067x10^-4) s^2 - 2.17 ]
 
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-34+14 = ? (It's not -24.)
 
oh shoot, stupid mistake! haha, thanks for the catch!
 
xpaulinabearx said:

Homework Statement



K(max) = (6.63x10^-34 J s)(7.09x10^14s) - 2.17x10^-19J
solve for kmax

The expression doesn't make sense from the outset: the units being added are not consistent.
(J*s)*s = J*s2, which is not the same as J alone, so these items cannot be added together meaningfully.

Perhaps the first item should be (6.63x10-34 J s-1) ?
 
The first constant is Planck's constant, which does have units of J s. The second quantity is supposed to be a frequency, with units of s-1. Probably just a typo on the OP's part.
 
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